Final answer to the problem
$\frac{3x^{6}+5x^{4}-2x^{5}-4x^{3}+6x}{\left(x^2+1\right)^2}$
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Step-by-step Solution
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Find the derivative using the quotient rule Find the derivative using the definition Find the derivative using the product rule Find the derivative using logarithmic differentiation Find the derivative Integrate by partial fractions Product of Binomials with Common Term FOIL Method Integrate by substitution Integrate by parts
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1
Apply the quotient rule for differentiation, which states that if $f(x)$ and $g(x)$ are functions and $h(x)$ is the function defined by ${\displaystyle h(x) = \frac{f(x)}{g(x)}}$, where ${g(x) \neq 0}$, then ${\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}$
$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)-\left(x^5-x^4+x^2-2\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
2
Simplify the product $-(x^5-x^4+x^2-2)$
$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)+\left(-x^5-\left(-x^4+x^2-2\right)\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
Intermediate steps
3
Simplify the product $-(-x^4+x^2-2)$
$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)+\left(-x^5+x^4-\left(x^2-2\right)\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
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Intermediate steps
4
Simplify the product $-(x^2-2)$
$\frac{\frac{d}{dx}\left(x^5-x^4+x^2-2\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
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5
The derivative of a sum of two or more functions is the sum of the derivatives of each function
$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(-2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}$
6
The derivative of a sum of two or more functions is the sum of the derivatives of each function
$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(-2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(1\right)\right)}{\left(x^2+1\right)^2}$
7
The derivative of the constant function ($-2$) is equal to zero
$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\left(\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(1\right)\right)}{\left(x^2+1\right)^2}$
8
The derivative of the constant function ($1$) is equal to zero
$\frac{\left(\frac{d}{dx}\left(x^5\right)+\frac{d}{dx}\left(-x^4\right)+\frac{d}{dx}\left(x^2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2\right)}{\left(x^2+1\right)^2}$
9
The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function
$\frac{\left(\frac{d}{dx}\left(x^5\right)-\frac{d}{dx}\left(x^4\right)+\frac{d}{dx}\left(x^2\right)\right)\left(x^2+1\right)+\left(-x^5+x^4-x^2+2\right)\frac{d}{dx}\left(x^2\right)}{\left(x^2+1\right)^2}$
Intermediate steps
10
The power rule for differentiation states that if $n$ is a real number and $f(x) = x^n$, then $f'(x) = nx^{n-1}$
$\frac{\left(5x^{4}-4x^{3}+2x\right)\left(x^2+1\right)+2\left(-x^5+x^4-x^2+2\right)x}{\left(x^2+1\right)^2}$
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Intermediate steps
11
Simplify the derivative
$\frac{3x^{6}+5x^{4}-2x^{5}-4x^{3}+6x}{\left(x^2+1\right)^2}$
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Final answer to the problem
$\frac{3x^{6}+5x^{4}-2x^{5}-4x^{3}+6x}{\left(x^2+1\right)^2}$